Respuesta :
supporting claim :
75% of 100 = 0.75 * 100 = 75
50% of 100 = 0.50 * 100 = 50
0.75(100) > 0.50(100) <== ur inequality
counter claim :
75% of -100 = 0.75 * -100 = -75
50% of -100 = 0.50 * -100 = -50
0.75(-100) < 0.50(-100) <== ur inequality
75% of 100 = 0.75 * 100 = 75
50% of 100 = 0.50 * 100 = 50
0.75(100) > 0.50(100) <== ur inequality
counter claim :
75% of -100 = 0.75 * -100 = -75
50% of -100 = 0.50 * -100 = -50
0.75(-100) < 0.50(-100) <== ur inequality
Answer with explanation:
Let a and be two numbers.
Leila says that 75% of a number will always be greater than 50% of any other number.
This means that:
0.75×a > 0.50×b
( Since 75% of a=0.75×a
and 50% of b =0.50×b )
1)
Numbers that support Leila's claim.
Let a=100 and b=10
0.75×a=0.75×100=75
and 0.50×10=5
As we know that:
75 > 5
Hence, a=100 and b=10 support Leila's claim.
2)
Numbers that refutes her claim.
Let a=1 and b=200
0.75×a=0.75×1=0.75
and 0.50×200=100
As we know that:
0.75 < 100
Hence, a=1 and b=200 refutes Leila's claim.