there are 9 red markers, 5 blue markers, 14 yellow markers, and 8 green markers in a pencil box. A marker is chosen at random, replaced, then another is chosen. Find each probability.
P(yellow, then red)
P(blue, then green)
P(both red)

Respuesta :

We will see that the probabilities are:

  • P(yellow, then red) = 0.1
  • P(blue, then green) = 0.03
  • P(both red) = 0.06

How to find the probabilities?

First, the probability of getting a particular color of marker is given by the quotient between the number of markers of that color and the total number of markers

There are:

9 red markers.

5 blue markers.

14 yellow markers

8 green markers.

For a total of: 9 + 5 + 14 + 8 = 36.

a) P(yellow, then red)

First, the probability of getting a yellow marker is:

p = 14/36.

Then the probability of getting a red marker (notice that now there are 35 markers in total) is:

q = 9/35.

Then the joint probability is:

P(yellow, then red) = p*q = ( 14/36)*(9/35) = 0.1

b) P(blue, then green)

First, the probability of getting a blue marker is:

p = 5/36.

After, the probability of getting a green marker is:

q = 8/35.

So the joint probability is:

P(blue, then green) = (5/36)*(8/35) = 0.03

c) P(both red).

First, the probability of getting a red marker is:

p = 9/36

Now there are 8 red markers and 35 markers in total, so the probability of getting another red marker is:

q = 8/35

The joint probability is:

P(both red) = (9/36)*(8/35) = 0.06

If you want to learn more about probability:

https://brainly.com/question/251701

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