The number of combinations is given by 1000
Using the Fundamental Counting Theorem, it is found that there are 1000 possible numbers that Lina could pick.
It is a theorem that states that if there are n things, each with [tex]n_1,n_2,........n_n[/tex] ways to be done, each thing independent of the other, the number of ways they can be done is:
[tex]N=n_1\times n_2\times n_2\times........ n_n[/tex]
In this problem:
The number is more than 5000, hence the first digit can be 5, 6, 7, 8, or 9, hence [tex]n_1=5[/tex] .
The second digit is prime, that is, 2, 3, 5, or 7, hence[tex]n_2=4[/tex].
For the third digit, there are no restrictions, hence [tex]n_3=10[/tex].
The number is odd, hence the fourth digit can be 1, 3, 5, 7, or 9, hence[tex]n_4=5[/tex] .
Hence the number of combinations is given by:
N = 5 x 4 x 10 x 5 = 1000
To learn more about the Fundamental Counting Theorem at:
brainly.com/question/24314866
#SPJ1