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A spinner and 4 cards are shown below:

A spinner with 5 equal sectors is shown in the figure. The colors Green, Blue, Purple, Yellow, and Red are marked on it. The arrow points at the purple color. Four cards are shown on the right side. The colors Red, Yellow, Blue, and Pink are marked on them.

Jane spins the spinner and selects a card without looking. What is the probability that the spinner stops at purple and a pink card is selected?

1 over 20
1 over 5
1 over 4
9 over 20

Respuesta :

Lenvy

Answer:

1 over 20

Step-by-step explanation:

Given that:

a spinner and 4 cards

A Spinner ⇒ 5 equal sectors;Color: Blue,Purple,Yellow,Red,Green

Arrow point at purple

Four cards ⇒ Color : Red,Yellow,Blue,Pink

Jane spins the spinner & selects card without looking.

To Find - Probability spinner stops at purple & select pink card.

Solve:

Multiply 4 (the number of cards) with 5 (The number of equal sectors)

[tex]\frac{1}{5}\times\frac{1}{4}=\frac{1}{20}[/tex]          {1 × 1 = 1}    {5×4=20}

~lenvy~

RevyBreeze

Answer:

1 over 20

Step-by-step explanation:

Given the following:

1 spinner and 4 cards

A Spinner which has 5 equal sectors;Color: Green, Blue,Purple,Yellow,Red.

{Arrow point at purple}

Four cards ⇒ which color are Red,Yellow,Blue,Pink

Jane spins the spinner & selects card without looking.

To Find →  Probability spinner stops at purple & select pink card.

Since, purple and pink only has one in each of Spinner/card

Thus,

Spinner (5 equal sectors - 1/5}

Card {4 cards - 1/4}

1/4 × 1/5 = 1/20

Hence, probability spinner stops at purple & select pink card is [A] 1/20

[RevyBreeze]

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