Respuesta :

pc192y

Answer:

58 units squared

Step-by-step explanation:

**I'm doing the question with the 7 by 3 triangle in the picture, not 777 by 333**

Pythagorean Theorem: [tex]a^2+b^2=c^2[/tex], where c is the length of the hypotenuse.

The given sides are legs, therefore, [tex]3^2+7^2=c^2[/tex]

[tex]9+49=c^2; 58=c^2; c=\sqrt{58}[/tex]

c is also one of the sides of the square. A square's area is one of the sides' lengths squared, so:

[tex](\sqrt{58}) ^{2}=58[/tex]

preciouspixie42

Answer:
58

Step-by-step explanation:

We can use the Pythagorean theorem to find the area of the square for the third side.

The equation for the Pythagorean theorem is

a^2 + b^2 = c^2

where a and b are the lengths of the two legs of the triangle, and c is the length of the hypotenuse.

a^2 + b^2 = c^2

3^2+7^2=x^2

9+49=x^2

58=x^2

The area of the square for the third side of the triangle is 58 units^2 squared.

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