contestada

A stone is thrown upwards with an initial velocity of 25 m/s at an angle of 30^0 to the ground. Without any calculations, state what the stone's vertical velocity will be when it again reaches ground level.

Respuesta :

Answer:

Explanation:

The vertical component of the velocity of stone = 25 sin 30 = 12.5 m/s .

Horizontal component = 25 cos 30 = 21.65 m/s

After the throw , the body will go upwards with reducing velocity  and at top position , its velocity becomes zero . Again it comes down and its velocity gains . When it reaches the surface , it regains its earlier velocity which was in the beginning of the throw that is 25 sin30 but in downward direction .

So its vertical velocity when it reaches the ground will be 25 sin 30 = 12.5 m/s in downward direction.