A 24-gauge copper wire has a radius of 0.11 mm and is used to connect a speaker to an amplifier. The speaker is located 20 m away from the amplifier. What is the minimum resistance of the connecting speaker wires at 20 ˚C?

Respuesta :

Given Information:

Radius of copper wire = r = 0.11 mm = 0.11×10⁻³ m

Length of copper wire = L = 20 m

Required Information:

Resistance of the copper wire = R = ?  

Answer:

Resistance of the copper wire = R = 18.1  Ω

Explanation:

The resistance of the copper wire is given by

[tex]R = \rho \frac{L}{A}[/tex]

Where ρ is the resistivity of the copper wire and is equal to 1.72×10⁻⁸ Ω/m at 20 ˚C, L is the length of the wire and A is the area of the wire and is given by

[tex]A = \pi r^{2}[/tex]

Since the wire is used to connect speaker to the amplifier, two wires would be needed and the length of the wire becomes

[tex]L = 2\times 20 = 40\: m[/tex]

Finally, the resistance of the wire is

[tex]R = \rho \frac{L}{\pi r^{2}}\\\\R = 1.72\times10^{-8}\cdot \frac{40}{\pi (0.11\times10^{-3})^{2}}\\\\R = 1.72\times10^{-8}\cdot 1.052\times10^{9}\\\\R = 18.1 \: \Omega[/tex]

Therefore, the minimum resistance of the connecting wires is 18.1 Ω

Answer:

Resistance = 181.8 ohms

Explanation:

R = L/r

R = 20/0.11

R = 181.8 ohms