Calculate the earth's gravity force on a 65 kg astronaut who is repairing the hubble space telescope 600 km above the earth's surface

Let Fgrav=earth's gravity force(N)=asked,
m1=mass of astronaut(kg)=65kg,
m2=mass of the earth(kg)=5.98x10^24 kg,
G=universal gravitation constant=6.673x10^-11 Nm^2/kg^2

d1=distance from the surface of the earth to its center=6.38x10^6m
d2=distance of the astronaut from the surface of the earth=600km=6x10^5m
d=d1+d2, since the astronaut is above the surface of the earth
d=6.38x10^6m + 6x10^5m=6,980,000m

Working equation: Fgrav=(Gm1m2)/d^2
Fgrav=(6.673x10^-11 Nm^2/kg^2)(65kg)(5.98x10^24 kg)/(6,980,000m)^2
Fgrav=532.38 N

johanrusli johanrusli · Answer 2 · 2020-01-02T13:26:16+01:00

Earth's gravity force on the astronaut is about 530 N

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Further explanation

Let's recall the Gravitational Force formula:

[tex]\boxed {F = G\ \frac{m_1 m_2}{R^2}}[/tex]

where:

F = Gravitational Force ( N )

G = Gravitational Constant ( = 6.67 × 10⁻¹¹ Nm²/kg² )

m = mass of object ( kg )

R = distance between object ( m )

Let us now tackle the problem!

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Given:

mass of astronaut = m = 65 kg

radius of Earth = R = 6400 km

mass of Earth = M = 6 × 10²⁴ kg

position height of the satellite = h = 600 km

orbit radius of the satellite = R + h = 7000 km = 7 × 10⁶ m

Asked:

gravity force = F = ?

Solution:

[tex]F = G \frac{ M m } { ( R + h )^2 }[/tex]

[tex]F = 6.67 \times 10^{-11} \times \frac { 6 \times 10^{24} \times 65 } { (7 \times 10^6)^2 }[/tex]

[tex]F \approx 530 \texttt{ N}[/tex]

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Learn more

Unit of G : https://brainly.com/question/1724648
Velocity of Runner : https://brainly.com/question/3813437

Kinetic Energy : https://brainly.com/question/692781

Acceleration : https://brainly.com/question/2283922

The Speed of Car : https://brainly.com/question/568302

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Answer details

Grade: High School

Subject: Mathematics

Chapter: Gravitational Force