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A train traveling at 48 m/s begins to slow down as it approaches a bend in the tracks. If it travels around the bend at a speed of 14 m/s, and it takes 40 seconds to properly slow down, what is the acceleration acting on the train during this time?


Please help 5 minutes left please!,

Respuesta :

niladripodder25

Answer:

Acceleration is (48-14)/40 m/s² = 34/40 m/s² = 0.85 m/s²

samueladesida43

The acceleration acting on the train during this time of travel is 0.85m/s²

HOW TO CALCULATE ACCELERATION:

  • The acceleration of a moving body can be calculated by using the formula below:

  • a = (v - u)/t

Where;

  1. a = acceleration (m/s²)
  2. v = final velocity (m/s)
  3. u = initial velocity (m/s)
  4. t = time (s)

  • According to this question, a = ?, v = 48m/s, u = 14m/s, t = 40s.

  • a = (48 - 14)/40

  • a = 34/40

  • a = 0.85m/s²

  • Therefore, the acceleration acting on the train during this time of travel is 0.85m/s².

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