Answer:
The truck must travel at a speed of 98.6677 km/hr to stay beneath the airplane
Explanation:
The given parameters are;
The velocity of the airplane, v = 105 km/hr
The direction of the airplane, θ = 25 degrees to the ground = 25°
Therefore, we have that the horizontal component of the velocity of the plane, vₓ is given as follows;
vₓ = v × cos(θ) = 105 km/hr × cos(25) ≈ 98.6677 km/hr
The vertical component of the velocity of the plane, [tex]v_y[/tex], is given as follows;
[tex]v_y[/tex] = v × sin(θ) = 105 km/hr × sin(25) ≈ 44.37 km/hr
The truck only has to travel at a speed equal to the horizontal velocity of the airplane to stay beneath the airplane
Therefore, the travelling speed the truck must be vₓ which is 98.6677 km/hr to stay beneath the airplane.
