A rectangle’s length is 4 more than twice its width. Its area is 240 square centimeters. Complete the work to find the dimensions of the rectangle. w(2w + 4) = 240 2w2 + 4w = 240 2w2 + 4w – 240 = 0 2(w + 12)(w – 10) = 0 What is the width of the rectangle? What is the length of the rectangle?

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Answer: The width is 10cm and the length is 24cm :)

Step-by-step explanation:

The width of the rectangle is 10 units long and the length of the rectangle is 14 units long.

What is the area of a rectangle?

Area of a rectangle is the product of the length of the rectangle and the width of the rectangle. It can be given as,

[tex]A=a\times b[/tex]

Here, (a)is the length of the rectangle and (b) is the width of the rectangle.

A rectangle’s length is 4 more than twice its width and Its area is 240 square centimeters.

Let w is the width of the rectangle. Thus,

[tex]w\times (2w + 4) = 240[/tex]

[tex]2w^2 + 4w = 240[/tex]

[tex]2w^2 + 4w - 240 = 0[/tex]

Factorize the equation as,

[tex]2(w + 12)(w - 10) = 0 \\ (w + 12)(w - 10) = 0 \\[/tex]

Equate the factors to find the width as,

[tex]w+12=0\\w=-12\\w-10=0\\w=10[/tex]

Taking positive value, the width of the rectangle is 10 units. The rectangle’s length is 4 more than twice its width. Thus,

[tex]l=4+10\\l=14[/tex]

Hence, the width of the rectangle is 10 units long and the length of the rectangle is 14 units long.

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