Respuesta :

Space

Answer:

6.96 × 10²³ molecules NaNO₃

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Atomic Structure

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

Step 1: Define

98.2 g NaNO₃

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of Na - 22.99 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of NaNO₃ - 22.99 + 14.01 + 3(16.00) = 85.00 g/mol

Step 3: Convert

  1. Set up:                               [tex]\displaystyle 98.2 \ g \ NaNO_3(\frac{1 \ mol \ NaNO_3}{85.00 \ g \ NaNO_3})(\frac{6.022 \cdot 10^{23} \ molecules \ NaNO_3}{1 \ mol \ NaNO_3})[/tex]
  2. Multiply:                                                                                                            [tex]\displaystyle 6.95718 \cdot 10^{23} \ molecules \ NaNO_3[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

6.95718 × 10²³ molecules NaNO₃ ≈ 6.96 × 10²³ molecules NaNO₃

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