Respuesta :
Answer:
[tex]24408[/tex]
Step-by-step explanation:
GIVEN: The local newspaper in Danville has seen its subscription go down [tex]10\%[/tex] each year. The paper currently has [tex]70000[/tex] subscribers.
TO FIND: How many subscribers will the paper have in [tex]10[/tex] years
SOLUTION:
Total subscribers newspaper have now [tex]=70,000[/tex]
rate of decline o subscribers in newspaper [tex]=10\%[/tex]
total subscriber after 1 year [tex]=70,000-\frac{10}{100}\times70,000=63,000[/tex]
total subscriber after 2 year [tex]=63,000-\frac{10}{100}\times63,000=56,700[/tex]
total subscriber after 3 year [tex]=56,700-\frac{10}{100}\times56,700=51030[/tex]
total subscriber after 4 year [tex]=51,030-\frac{10}{100}\times51,030=45927[/tex]
total subscriber after 5 year [tex]=45,927-\frac{10}{100}\times45,927\approx41334[/tex]
total subscriber after 6 year [tex]=41,334-\frac{10}{100}\times41,334\approx37201[/tex]
total subscriber after 7 year [tex]=37,201-\frac{10}{100}\times37,201\approx33,481[/tex]
total subscriber after 8 year [tex]=33,481-\frac{10}{100}\times33,481\approx30,133[/tex]
total subscriber after 9 year [tex]=30,133-\frac{10}{100}\times30,133\approx27120[/tex]
total subscriber after 10 year [tex]=27,120-\frac{10}{100}\times27,120\approx24408[/tex]
Hence the total subscribers in [tex]10[/tex] years will be [tex]24408[/tex]
