A:
[tex]F=\frac{9}{5}C+32 \\ \\
F-32=\frac{9}{5}C \\ \\
\boxed{C=\frac{5}{9}(F-32)}[/tex]
B:
[tex]F=10^\circ F \\ \\
C=\frac{5}{9}(F-32)=\frac{5}{9}(10-32)=\frac{5}{9} \times (-22)=\frac{-110}{9}=-12\frac{2}{9} \\ \\
\boxed{C=-12 \frac{2}{9} ^\circ C}[/tex]
C:
[tex]-np-70\ \textgreater \ 40 \ \ \ \ \ \ |\hbox{add 70} \\ \\
-np\ \textgreater \ 110 \ \ \ \ \ \ \ \ \ \ \ |\hbox{divide by (-p), flip the sign} \\ \\
\boxed{n\ \textless \ -\frac{110}{p}}[/tex]