Answer:
The function will be,
[tex]h = (98 - 16 \times t^{2})[/tex] (in feet)
Step-by-step explanation:
We know that acceleration due to gravity in F.P.S system is given by,
[tex]32 \frac {{\txtrm}{ft}}{{\txtrm}{second^{2}}}[/tex] and if a body is dropped from a height of [tex]h_{1}[/tex] feet to fall to the ground then after t seconds it's height above the ground will be given by,
[tex]h = (h_{1} - \frac {1}{2} \times g \times t^{2})[/tex] feet [where the acceleration due to gravity is given by g] provided it is greater than or equal to zero.
here, [tex] g = 32 \frac {{\txtrm}{ft}}{{\txtrm}{second^{2}}}[/tex]
and [tex]h_{1} = 98[/tex] feet
So,
[tex]h = (98 - \frac {1}{2} \times 32 \times t^{2})[/tex]
⇒ [tex]h = (98 - 16 \times t^{2})[/tex] [in feet]
