Answer:
The number of miles driven this month is 0.7 times miles driven last month .
Step-by-step explanation:
Given statement as :
The number of miles driven this month was a 30% decrease of the number of miles driven last month
Let The number of miles drives last month = L miles
And The number of miles drives this month = P miles
The rate of decrease in the number of miles from last months to this month = 30 %
The time period = 1 months
Now, according to question
The number of miles drives present month = The number of miles drives last month × [tex](1-\dfrac{\textrm rate}{100})^{\textrm time}[/tex]
Or, P miles = L miles × [tex](1-\dfrac{\textrm 30}{100})^{\textrm 1}[/tex]
Or, P miles = L miles × [tex]\frac{100-30}{100}[/tex]
Or, P miles = L miles × [tex]\frac{70}{100}[/tex]
∴ P = L × 0.7 months
So, This month = 0.7 times last month
Hence The number of miles driven this month is 0.7 times miles driven last month . Answer
