Answer:
0.00956770833 T
Explanation:
q = Charge of electron = [tex]1.6\times 10^{-19}\ C[/tex]
m = Mass of proton = [tex]1.67\times 10^{-27}\ kg[/tex]
a = Acceleration = [tex]2.2\times 10^{13}\ m/s^2[/tex]
v = Velocity = [tex]2.4\times 10^{7}\ m/s[/tex]
Magnetic field is given by
[tex]B=\dfrac{ma}{qv}\\\Rightarrow B=\dfrac{1.67\times 10^{-27}\times 2.2\times 10^{13}}{1.6\times 10^{-19}\times 2.4\times 10^{7}}\\\Rightarrow B=0.00956770833\ T[/tex]
The magnetic field is 0.00956770833 T
