Respuesta :
- Answer:
- Probability of getting a die which 5 does not appear on each side is 5/6
- probability of getting numbers of which the difference is 2 is 1/9
- Probability of obtaining numbers that the sum is equal to or greater than 10 is 1/12
Step-by-step explanation:
When two dies are tossed, possible outcomes are (1,1) (1,2) ,(1,3) (1,4), (1,5) (1,6),(2,1) (2,2) (2,3) (2,4) (2,5) (2,6), (3,1)(3,2)(3,3)(3,4),(3,5)(3,6)(4,1) (4,2),(4,3)(4,4)(4,5)(4,6)(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)
so the total sample space =36
From de possible outcome, probability of getting a die that five does not appear on either side is given by total outcome of not getting five from either side/sample space
=30/36 = 5/6
And also probability of getting the difference of numbers to be 2 are (3,1)(4,2) (5,3) (6,4) =4outcomes
the probability of getting a difference of 2 is given by outcome/sample space 4/36 = 1/9
probability of getting the summation of two numbers to be equal to or greater than ten are; Outcome/sample space.
the outcome are (4,6) (5,5) (5,6)(6,4)(6,5)and (6,6)= 6outcomes
=6/36 =1/12.