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Find the molecular formula for a compound with-
4.04 g N, 11.46 g O, molar mass 108.0 g/mol.
? moles N =
? moles O =
N : O =
empirical formula =
molecular mass of empirical formula =
The molar mass ratio of (molecular formula/empirical formula) =
molecular formula =

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Answer:

moles of N

4.04 g / 14.01 = 0.288

moles of O

11.46 / 16 = 0.72 moles

divide both of them by the lowest number of moles to get the ratio

0.288 / 0.288= 1

0.72 / 0.288 = 2.48

now multiply both by 2, to make it a whole number =

ratio = 2 : 5

empirical formula = N2O5

the molar mass of the compound = 108.01

molar mass of the empirical formula = 108.02

when you divide this to get the factor the factor is also 1, so you dont really change anything

FORMULA = N2O5

Explanation:

I had it written done from my school notes

I really hope this helps

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