contestada

The letters that form the word ALGEBRA are
placed in a bowl. What is the probability, as a
percent, of choosing a letter other than A
and then choosing an A?

Respuesta :

frika

Answer:

Nearly 23.8%

Step-by-step explanation:

The word ALGEBRA consists of letters A, L, G, E, B, R and A (2 letters A and 5 letters other than A).

The probability that the first letter chosen will be other than A is

[tex]\dfrac{5}{7}[/tex]

Then 2 letters A and 4 letters other than A left (6 letters in total). The probabilty that the second letter chosen is A is

[tex]\dfrac{2}{6}=\dfrac{1}{3}[/tex]

Hence, the probability of choosing a letter other than A and then choosing an A is

[tex]\dfrac{5}{7}\cdot \dfrac{1}{3}=\dfrac{5}{21}\approx 23.8\%[/tex]