The diagonals are: diagonal₁=2x+3y diagonal₂=(x+8)+(2y+5) We have to solve the following system of equations: 2x=3y (x+8)=(2y+5) We solve this system by substitution method: 2x=3y ⇒x=3y/2
(3y/2 +8)=2y+5 3y+16=4y+10 -y=-6 y=6
x=3y/2=3*6/2=9
we obtain the measure of the diagonals: diagonal₁=2x+3y=2*9+3*6=18+18=36 diagonal₂=(x+8)+(2y+5)=(9+8)+(2*6+5)=17+17=34
