Answer:
[tex]\frac{1}{2} QP = UT[/tex]
Step-by-step explanation:
We are given a ΔPQR in which S is the mid point of QP , T is the mid point of QR , U is the mid point of PR
i) is true
⇒ [tex]\frac{1}{2} QP = UT[/tex]
Using mid segment theorem which states that In a triangle, the line joining the midpoints of any two sides will be parallel to the third side and that same line joining the midpoints is also half of length of third side .
So, by refering image we can see that UT is the line joining the two mid points . So, by using above theorem 1/2QP=UT and UT is parallel to PQ
Thus, (i) statement is true
⇒[tex]\frac{1}{2} QP = UT[/tex]
