Answer:
[tex]13\frac{7}{16}[/tex] laps can Fred run in one hour.
Step-by-step explanation:
Given Statement: Fred is running on the school track. He can run [tex]10\frac{3}{4}[/tex] laps in [tex]\frac{4}{5}[/tex] of an hour.
Unit rate are expressed as a quantity of 1, such as 3 feet per second or 7 miles per hour, they are called unit rates
From the given condition we have;
In [tex]\frac{4}{5}[/tex] he can run [tex]\frac{43}{4}[/tex] laps
Unit rate per hour = [tex]\frac{\frac{43}{4} }{\frac{4}{5} }[/tex]
=[tex]\frac{43}{4} \times \frac{5}{4} = \frac{215}{16}[/tex] laps
Therefore, Fred can run in one hour is, [tex]13\frac{7}{16}[/tex] laps.
