Respuesta :
Let U = {all integers}.
Consider the following sets:
A = {x | x ∈ U and x > 3}
B = {x | x ∈ U and x is an even integer}
C = {x | x ∈ U and 2x is an odd integer}
D = {x | x ∈ U and x is an odd integer}
Use the defined sets to answer the questions.Assuming 0 is an even integer, which set is the complement to set B?
D
Which set is an empty set?
C
Which set would contain the subset E = {1, 3, 5, 7}?
D
You can use the definition of complement of a set to find the complement of set B.
- The complement set to B is B' = D
- The set C is an empty set.
- The set which contains E = {1. 3. 5. 7} is D
What is a complement of a set?
Firstly there is a universal set in which all the remaining sets in the given context lies. Now, let the target set be B whose complement set has to be found. Let the universal set be U, then we have the complement set of B as:
B' = U - B (remove all elements from the set U which lies in set B)
or it is written as:
[tex]B' = \{ x \in U | x \notin B\}[/tex]
Thus, we can write the complement set of B in two ways:
[tex]B' = \{ x \in U | x \notin B\}[/tex]
or
B' = U - {x | x ∈ U and x is an even integer}
B' = {x | x ∈ U and x is an odd integer} = D (since if an integer is not even, then it must be odd)
The set C is empty since 2x for an integer x is always even (considering the given fact that 0 is to be assumed even too). Since no 2x is going to be odd, thus, C is an empty set.
Since set A contains all integer > 3, and set B contains even integers and set C is empty, and since set D contains all odd integers, thus the set D contains the given set E = {1, 3, 5, 7}
Thus, we have:
- The complement set to B is B' = D
- The set C is an empty set.
- The set which contains E = {1. 3. 5. 7} is D
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