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2. A basket contains 6 apples, 5 bananas, 4 oranges and 5 peaches. If you randomly choose one piece of fruit, eat it and then choose another, what is the probability that you would choose a banana and then an apple? (Enter your answer as a whole number percent.)

Respuesta :

Answer:

8% as a whole number percent

Step-by-step explanation:

Number of;

Apples = 6

Bananas = 5

Oranges = 4

Peaches = 5

Total number of fruits in the basket = 6 + 5 + 4 + 5

= 20

Probability of picking a banana and then an apple

= (5/20) × (6/19)

= 30/380

= 3/38

=7.89% ≈ 8%

The probability that you would choose a banana and then an apple is; 8%

What is the Probability?

We are given that there are;

6 apples

5 bananas

4 oranges

5 peaches

Total number of fruits = 6 + 5 + 4 + 5 = 20

Probability of picking a banana and then an apple = (5/20) * (6/19)

⇒ 3/38

In percentage ≈ 8%

Read more about Probability at; https://brainly.com/question/251701

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