The area of the given trapezoid in a figure ABCD is 66 square inches
We have given that the,
A trapezoid ABCD is drawn with a length of parallel sides AB and CD equal to 10 inches and 12 inches, respectively.
The length of one of the non-parallel sides of BC is 6 inches.
Side BC is perpendicular to DC.
A perpendicular line drawn from A to side CD meets CD at E.
What is the area of the trapezoid?
The area of a trapezoid is the number of unit squares that can be fit into it and it is measured in square units.
We have
The area of the rectangle is given by,
Area of the rectangle= 10 x 6
Area of the rectangle= 60
Then, The area of the triangle is,
[tex]Area \ of \ the\ triangle=\frac{1}{2}\times height\times base[/tex]
[tex]Area \ of \ triangle=\frac{1}{2}\times 6\times2 \\Area \ of \ triangle=6inch^2[/tex]
Therefore the area of the trapezoid is,
Area of the triangle+ area of rectangle= Area of the trapezoid
Area of the trapezoid= 60 + 6
Area of the trapezoid = 66inches^2
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