Respuesta :
C(Molarity)=n(mole of solute)/V(L of solution)
36g/(180g/mol) = 0.2mol of glucose
C = 0.2mol/2L = 0.1M(mol/L)
36g/(180g/mol) = 0.2mol of glucose
C = 0.2mol/2L = 0.1M(mol/L)
Answer:- Molarity of the glucose solution is 0.1M.
Solution:- Molarity is moles of solute per liter of the solution.
From given info, 36.0 grams of glucose are present in a 2.0 L solution. We need to convert the grams to moles using molar mass and then divide the moles by the liters to get the molarity.
First step, grams to moles conversion:
[tex]36.0g(\frac{1 mol}{180 g})[/tex]
= 0.2 mol
Second step, calculations for molarity:
molarity = [tex]\frac{0.2 mol}{2.0 L}[/tex]
= 0.1M
(where, M stands for molarity)
So, the molarity of the glucose solution is 0.1M.
