Respuesta :
I'd start by finding the roots of the given expression. From these roots you can write the factors.
-28 plus or minus sqrt(28^2 - 4(5)(-12)
x = ------------------------------------------------------
10
-28 plus or minus sqrt(784+240)
= -----------------------------------------------
10
-28 plus or minus 35 (approx)
= ---------------------------------------------
10
35-28 -28-35
= ------------- and ------------ These roots are only approximate. However,
10 10 if we treat them as exact, with one root
equal to 7/10 and the other -63 / 10
then the factors of the polynomial would be, approx., x-7/10 and x+63/10.
Please double check to ensure that you've copied down the problem completely and accurately. Thanks.
-28 plus or minus sqrt(28^2 - 4(5)(-12)
x = ------------------------------------------------------
10
-28 plus or minus sqrt(784+240)
= -----------------------------------------------
10
-28 plus or minus 35 (approx)
= ---------------------------------------------
10
35-28 -28-35
= ------------- and ------------ These roots are only approximate. However,
10 10 if we treat them as exact, with one root
equal to 7/10 and the other -63 / 10
then the factors of the polynomial would be, approx., x-7/10 and x+63/10.
Please double check to ensure that you've copied down the problem completely and accurately. Thanks.
The answer is (x+6) x (5x-2)
Change 5x ^2 + 28x - 12
To:
5x^2 + 30x - 2x - 12
Factor the expression
5x (x + 6) - 2 ( x + 6)
Factor out x + 6
To get
(x + 6) (5x-2)
that’s the answer because their are no like terms.
Change 5x ^2 + 28x - 12
To:
5x^2 + 30x - 2x - 12
Factor the expression
5x (x + 6) - 2 ( x + 6)
Factor out x + 6
To get
(x + 6) (5x-2)
that’s the answer because their are no like terms.