Respuesta :
Rate of Effusion of Unknown gas = rX = 0.5
Rate of Effusion of Hydrogen = rH = 1
M.mass of Hydrogen = mH = 2 g/mol
M.mass of Unknown gas = mX = ?
Formula used:
rH / rX = √mX / mH
taking square on both sides,
r²H / r²X = mX / mH
Solving for mX,
mX = (r²H ÷ r²X) × mH
Putting values,
mX = [1² ÷ (0.5)²] × 2 g/mol
mX = (1 ÷ 0.25) × 2 g/mol
mX = 4 × 2 g/mol
mX = 8 g/mol
Result:
Molecular Mass of Unknown gas is 8 g/mol.
Rate of Effusion of Hydrogen = rH = 1
M.mass of Hydrogen = mH = 2 g/mol
M.mass of Unknown gas = mX = ?
Formula used:
rH / rX = √mX / mH
taking square on both sides,
r²H / r²X = mX / mH
Solving for mX,
mX = (r²H ÷ r²X) × mH
Putting values,
mX = [1² ÷ (0.5)²] × 2 g/mol
mX = (1 ÷ 0.25) × 2 g/mol
mX = 4 × 2 g/mol
mX = 8 g/mol
Result:
Molecular Mass of Unknown gas is 8 g/mol.
I had done the quiz twice and got this question incorrect twice. While they wouldn't show me the real answer I do know that 1.008 and 2.0 aren't the answer and based on the rating for the answer below it's probably not D. 8 g/mol. So your answer must be B. 4.064.
If my answer helped and was correct please rate it so other people know. If it wasn't or was leave a comment so other people know.
Thanks