Respuesta :
Given that the angle measure 20 and the side opposite to that angle measures 10 cm, suppose this is the height of the triangle, the hypotenuse
Such that
sin theta=opposite/hypotenuse
opposite=a=10 cm
sin 20=10/h
multiplying both sides by h we get
hsin20=10
hence;
h=10/sin20
h=29.24 cm
h=29.2 cm
Such that
sin theta=opposite/hypotenuse
opposite=a=10 cm
sin 20=10/h
multiplying both sides by h we get
hsin20=10
hence;
h=10/sin20
h=29.24 cm
h=29.2 cm
By using a trigonometric relation, we will see that the hypotenuse measures 29.2 cm.
How to get the length of the hypotenuse?
Here we have a right triangle, and we know that one angle measures 20° and the opposite cathetus measures 10cm.
Here we can use the relation:
sin(a) = (opposite cathetus)/(hypotenuse)
In this case, we have:
- a = 20°
- opposite cathetus = 10cm
- hypotenuse = H
Replacing that we get:
sin(20°) = 10cm/H
Solving for H we get:
H = 10cm/sin(20°) = 29.2 cm
If you want to learn more about right triangles, you can read:
https://brainly.com/question/2217700