Respuesta :

musiclover10045
(y^2 + 7y +12) / (y^2+8y +15)

factor both equations:

(y+3)(y+4) / (y+3) (y+5)

cancel out common factors to get:

y+4 / y+5
Astute
[tex]((((y^2) + 7y) + \frac{12}{y^2} + 8y) + 15 \\ \\ \boxed{y^2+7y= \frac{y^2+7y}{1} = \frac{y^2+7y)*y^2}{y^2} } \\ \\ (pulling \ out \ like \ terms) \\ \\ y^2 + 7y = y * (y + 7) \\ \\ (Your \ answer): \boxed{\bf{y+4 / y+5}}[/tex]

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