Respuesta :
THis is a binomial distribution:-
P( 3 tails) = 15C3 (0.5)^3(0.5)^12
= 0.0139
P(5 tails) = 15C5 (0.5)^5(0.5)^10
= 0.0916
P(3 or 5) = 0.0139 + 0.0916 = 0.1055 Answer
P( 3 tails) = 15C3 (0.5)^3(0.5)^12
= 0.0139
P(5 tails) = 15C5 (0.5)^5(0.5)^10
= 0.0916
P(3 or 5) = 0.0139 + 0.0916 = 0.1055 Answer
Number of times = 15
[tex]\text {Probability of tails exactly 5 times :}[/tex]
[tex] \left(\begin{array}{cc}15\\3\end{array}\right) \bigg( \dfrac{1}{2} \bigg)^{15} = \dfrac{3003}{32768} [/tex]
[tex]\text {Probability of tails exactly 3 times :}[/tex]
[tex]\left(\begin{array}{cc}15\\3\end{array}\right) \bigg( \dfrac{1}{2} \bigg)^{15} = \dfrac{455}{32768}[/tex]
Total probability:
[tex]\dfrac{3003}{32768} + \dfrac{455}{32768} = \dfrac{1729}{16384} = 0.11 \text { \sqrt{x} (nearest hundred)}[/tex]
[tex]\text {Probability of tails exactly 5 times :}[/tex]
[tex] \left(\begin{array}{cc}15\\3\end{array}\right) \bigg( \dfrac{1}{2} \bigg)^{15} = \dfrac{3003}{32768} [/tex]
[tex]\text {Probability of tails exactly 3 times :}[/tex]
[tex]\left(\begin{array}{cc}15\\3\end{array}\right) \bigg( \dfrac{1}{2} \bigg)^{15} = \dfrac{455}{32768}[/tex]
Total probability:
[tex]\dfrac{3003}{32768} + \dfrac{455}{32768} = \dfrac{1729}{16384} = 0.11 \text { \sqrt{x} (nearest hundred)}[/tex]
