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Choose the lewis structure for the hypobromite ion, bro−. choose the lewis structure for the hypobromite ion, . the [br-o]^- ion with three lone-pairs of electrons on the bromine atom, and three on the oxygen atom the [br-o]^- ion with no lone pairs of electrons shown on either the bromine nor the oxygen atom. the ion {^-}br-o, showing a formal charge of -1 on the bromine atom and three lone-pairs of electrons on both the bromine and the oxygen atoms. the [br-o]^- ion with three lone-pairs of electrons on the bromine atom, and one on the oxygen atom. the ion {^-}br-o, showing a formal charge of -1 on the bromine atom and no lone pairs of electrons on either the bromine nor the oxygen atom.

Respuesta :

transitionstate
Hypobromite Ion is as follow,
                                           
                                           BrO⁻

For Lewis structure, first add all the valence electrons of elements.
So,
                                Br  =  7
                                 O  =  6 
                                    ------------
                            Total  =  13
As there is one negative charge, add 1 electron in total valence electrons,
So,
                                  13
                                +  1
                              ----------
                                  14
Now, write both elements and make a single bond between them, and subtract 2 electrons for that single Bond.

                                  Br-O

We are now left with 12 electrons,

Start putting these 12 electrons on both elements so that each get 3 lone pair of electrons with complete octet,

The Final Lewis structure is as follow,
Ver imagen transitionstate

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