The sides of a square field are 16 meters. A sprinkler in the center of the field sprays a circular area with a diameter that corresponds to a side of the field. How much of the field is not reached by the sprinkler? Round your answer to the nearest hundredth. Use 3.14 for π.

Respuesta :

16 divided by [tex] \pi [/tex]=answer

Answer:

The answer is 55.04 square meters.

Step-by-step explanation:

The sides of a square field are 16 meters.

A sprinkler in the center of the field sprays a circular area with a diameter that corresponds to a side of the field.

So, we can say that the maximum circle that can be in the square will have the diameter of 16 meters.

That gives the radius as = 8 meters

Area of the square is = [tex]16\times16=256[/tex] square meters

Now, area of the circle = [tex]\pi r^{2}[/tex] = [tex]3.14\times8\times8=200.96[/tex] square meters

So, the area that the sprinkler does not cover is

[tex]256-200.96=55.04[/tex]square meters.