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If you are pushing on a box with a force of 20 N and there is a force of 7 N on the box due to sliding friction, what is the net force on the box? I need the answer ASAP!

Respuesta :

I think you would do 20+7 = 27N as the net force

Answer:

Net force acting on the box, [tex]F_{net}=13\ N[/tex]

Explanation:

It is given that,

Force with which the box is pushed, F = 20 N

Force acting due to sliding friction, f = 7 N

Sliding friction is a type of resistive force. It always opposes the motion of an object. Here, the force of 7 N will act in the opposite direction of motion. As a result, the net force acting on the box is given by :

[tex]F_{net}=F-f[/tex]

[tex]F_{net}=20-7[/tex]

[tex]F_{net}=13\ N[/tex]

So, the net force acting on the box is 13 N. Hence, this is the required solution.

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