i am not very good at math but i wanna say this is how you do it not a 100% sure
y = u + 2e^u
dy/du = 1 + 2e^u
u = 1 + ln x
du/dx = 1/x
Then dy/dx = dy/du * du/dx
dy/dx = (1+2e^u) * 1/x
Now replace u with 1 + ln x
dy/dx = (1 + 2e^(1+lnx)) * 1/x
dy/dx = (1 + 2e^1 * e^ln x) * 1/x
dy/dx = (1 + 2e x) * 1/x
dy/dx = 1/x + 2e
Now let x = 1/e. Then
dy/dx = 1/(1/e) + 2e = e + 2e = 3e
