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No. Of times bee beats in 1 sec=250
Average time =?
Frst find how many times bee beats in 1 min.
No. Of times bee beats in 1 min= 250*60=15000
Average time= 15000/ 250
Average time=60 times
nandhini123

Answer:

The average time for a single beat of bee’s wing is 0.004 seconds.

Step-by-step explanation:

Given:

Number of times bee beats its wings each second=250 times  

To Find:

average time for a single beat of a bee's wing =?

Solution:

Time required for single beat = (1 second)/(number of beats in 1 second)  

Substituting the values,

[tex]Time required for single beat = \frac{1}{250}[/tex]

Time required for single beat= 0.004

Hence, the average time for a single beat of bee’s wing is 0.004 seconds.