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Find the vertex of y = x2 + 14x − 40 by completing the square. A. (−7, 89) B. (−89, −7) C. (7, 89) D. (−7, −89)

Respuesta :

Alright, lets get started.

[tex] y = x^2 + 14 x - 40 [/tex]

For making complete square, we will add and subtract 49 in this

[tex] y = x^2 + 14 x - 40 + 49 - 49 [/tex]

[tex] y = x^2 + 14 x + 49 -40 - 49 [/tex]

[tex] y = (x+7)^2 - 40 - 49 [/tex]

[tex] y = (x+7)^2 - 89 [/tex]

Comparing the standard equation of parabola

[tex] y = a (x-h)^2 + k [/tex] where (h,k) are vertex

So, comparing the equation with standard one, h, k would be = (-7 , -89)

So, the vertex are (-7 , -89) : Answer

Hope it will help :)

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