[tex] \frac{ {a}^{ - 3} }{ {a}^{2}.a} [/tex]
In the denominator as you can see that the bases are same, Therefore we're gonna add those powers.
something like this:
[tex]= \frac{ {a}^{ - 3} }{ {a}^{2 + 1} } \\ = \frac{ {a}^{ - 3} }{ {a}^{3} } [/tex]
As we take the numerator to the denominator (when the base is same) then, the powers are turned to negative something like this:
[tex] \frac{1}{ {x}^{3} } \\ = 1 \times {x}^{ -3} \\ = {x}^{ - 3} [/tex]
So we'll do the same thing here,
[tex] {a}^{ - 3} \times {a}^{ - 3} [/tex]
Bases are same so once again add the powers,
[tex] {a}^{ (- 3 ) + (- 3)} [/tex]
and you'll get :
[tex] {a}^{ - 6} [/tex]
which is the same thing as
[tex] \frac{1}{ {a}^{6} } [/tex]
