A hot water heater measures 20" in diameter. What is the area of a metal base for the water heater, assuming a 2 inch overhang around the base of the water heater? (Round to the nearest tenth.) square inches.

Respuesta :

If you add the extra 2 inches in each side and give the base a diameter of 24. The area comes out to 452.39. The answer is 452.39.

Area of the metal base of the water heater is equals to 452.6 square inches.

What is area of a circle?

"Area of a circle is the region enclosed by the circle in two dimensional plane."

Formula used

Area of a circle = πr²

Value of π = 22 /7

According to the question,

Given diameter = 20 inches

2 inches extended around the base of the water heater

    New diameter = 24 inches

Therefore, radius = 12inches

Substitute the value of radius and π in the formula we get ,

Area of the base of the water heater = ( 22/ 7) ×(12)²

                                                            = 452.57 square inches

                                                         = 452.6 square inches (nearest tenth)

Hence, area of the metal base of the water heater is equals to 452.6 square inches.

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