two large crates are experiencing a gravitational force of 1.87 x 10^-4 N toward each other, represented by the force vector in this image. what is the value of M2? will vote brainliest
Use Pythagorean theorem to find r: [tex] \sqrt{95 {}^{2} + 78 {}^{2} } [/tex] [tex] \sqrt{9025 + 6084} [/tex] [tex] \sqrt{15109} [/tex] r=√15109 m
Now substitute all values: F=G×m1×m2/r² 1.87×10^-4=6.67×10^-11×185000×m2/√15109² 0.000187=0.0000000000667×185000×m2/15109 0.000187=1.23×10^-5×m2/15109 Multiply by 15109 by both sides: 2.83=1.23×10^-5×m2 m2=230081=2.3×10^5
