Co(g)+h2o(g)⇌co2(g)+h2(g) kp=0.0611 at 2000 k a reaction mixture initially contains a co partial pressure of 1320 torr and a h2o partial pressure of 1760 torr at 2000 k. calculate the equilibrium partial pressure of co2.

Question

11-03-2018
Chemistry

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Co(g)+h2o(g)⇌co2(g)+h2(g) kp=0.0611 at 2000 k a reaction mixture initially contains a co partial pressure of 1320 torr and a h2o partial pressure of 1760 torr at 2000 k. calculate the equilibrium partial pressure of co2.

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According to the reaction:
by set ICE table:
CO(g) + H2O(g) ↔ CO2(g) + H2(g)
initial 1320 1760 0 0
change -X -X +X +X
initial (1320-X) (1760-X) X X

when Kp = (pressure products)/ (pressure reactants )
Kp = P(H2)* P(CO2) /P(CO) * P(H2O)
by substitution:
0.0611 = (X * X) / (1320-X) * (1760-X)
0.0611 = X^2 / (X^2-3080X + 2323200)

∴X = 301 torr
∴P(CO2) = X = 301 torr