Respuesta :
Step 1: find number of moles of Mg(divide 4.03 by its molor mass)
step 2:find number of moles in O2
step 3: remember STP is 22.4 L = 1 mole
step 4: multiply 0.0829mol O₂ by 22.4L/mol to get 1.857L
answer is 1860 mL
step 2:find number of moles in O2
step 3: remember STP is 22.4 L = 1 mole
step 4: multiply 0.0829mol O₂ by 22.4L/mol to get 1.857L
answer is 1860 mL
Answer: 1860 mL
Explanation:
[tex]2Mg+O_2\rightarrow 2MgO[/tex]
According to Avogadro's law , 1 mole of every gas occupies 22.4 L at standard temperature and pressure and 1 mole of every substance weighs equal to its molar mass.
[tex]2moles=2\times 24.305=48.61g[/tex] of Magnesium reacts with 22.4 L of oxygen gas STP.
4.03g of Magnesium reacts with=[tex]\frac{22.4L}{48.61g}\times 4.03g=1.86L=1860ml[/tex] of oxygen gas STP.
