A drawer contains 4 red socks, 3 white socks, and 3 blue socks. Without looking, you select a sock at random, replace it, and select a second sock at random. What is the probability that the first sock is blue and the second sock is red?

Respuesta :

The probability that the first sock is blue and the second sock is red is:
(3/10) * (4/10)=3/25.

Answer:

[tex]\texttt{Probability}=\frac{3}{25} [/tex]

Step-by-step explanation:

Probability is the ratio of number of favorable outcome to total number of outcomes.

Total number of socks = 4 + 3 + 3 = 10

Number of blue socks = 3

Number of red sock = 4

[tex]\texttt{Probability of selecting blue sock}=\frac{3}{10} \\ [/tex]

[tex]\texttt{Probability of selecting red sock}=\frac{4}{10} \\ [/tex]

For finding the combined probability we need to multiply both the values

[tex]\texttt{Probability that the first sock is blue and the second sock is red}=\frac{3}{10}\times \frac{4}{10}=\frac{12}{100}=\frac{3}{25} \\ [/tex]

[tex]\texttt{Probability}=\frac{3}{25} [/tex]