Respuesta :

TSO
[tex]36x^2 + 11x - 35=0\\\\ \frac{-b \pm \sqrt{ b^2 -4( a)(c)} }{2(a)}\\\\ \frac{-11\pm \sqrt{11^2 -4(36)(-35)} }{2(36)}\\ \\ \frac{-11\pm \sqrt{5161 } }{72}\\\\\\ x = 0.8450013919812116\\\\ \text{ } x = -1.1505569475367672[/tex]
6x(6x) + 11x - 35 = 0
36x^2 + 11x - 35 = 0
36x^2 + 11x = 35
  
-11 + or -  square root 11^2 - 4 (36) (-35)
                      divided by 
                         2 * 36 

-11 + or - square root 5161
                   divided by
                        72

-11 + or - 71.84
     divided by
          72

There are two answers to the problem:
-11 + 71.84 / 72 = -10 rounded
-11 - 71.84 / 72 = -12. rounded
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