Respuesta :

Billymkhoi
y^2= 15y -56
⇒ y^2 -15y+ 56= 0
⇒ y=  \frac{-(-15)+ \sqrt{(-15)^2-4(1)(56)} }{2*1} 
or y= \frac{-(-15)- \sqrt{(-15)^2-4(1)(56)} }{2*1} 
⇒ y= 8 or y= 7

The final answer is y= 8 or y= 7~
TSO
[tex]y^2 = 15y - 56\\\\y^2 - 15y + 56 = 0\\\\ \frac{-b \pm \sqrt{ b^2 -4( a)(c)} }{2(a)}\\\\ \frac{15\pm \sqrt{(-15)^2 -4(1)(56)} }{2(1)}\\\\ \frac{15\pm \sqrt{1 } }{2}\\\\ \frac{15\pm 1 }{2}\\\\\frac{16}{2}, \frac{14}{2}\\\\8, 7[/tex]

The solution is 7 and 8.

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