Respuesta :
Answer: The correct answer is 'increases to 100 times the original concentration'.
Explanation:
let the initial pH be x
The original concentration of [tex][H^+][/tex] initially present be y
[tex]x=-log[y][/tex]...(1)
Final concentration of [tex][H^+][/tex] when pH reduced by 2 be z
[tex]x-2=-log[z][/tex]...(2)
Putting the value of 'x' from (1) into (2) we get :
[tex]-log[y]-2=-log[z][/tex]
[tex]z=10^2y=100y[/tex]
When pH of a solution decreases by 2.0, hydronium ion concentration of the solution increases to 100 times the original concentration