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When a container is filled with 3 moles of helium gas, 2 moles of oxygen gas, and 1 mole of carbon dioxide gas, the pressure in the container is 786 kPa. What is the partial pressure of the oxygen gas?
A. 131 kPa
B. 262 kPa
C. 393 kPa
D. 786 kPa

Respuesta :

W0lf93
The mole fraction of oxygen gas is 2/6 =1/3, because there are 6 total moles of gas in the container. The partial pressure can be found by multiplying this mole fraction by the total pressure. So the answer is B. 262 kPA because 1/3(786)=262.

Answer:

B. 262 kPa

Explanation:

First we must find the total of moles in the container:

3 moles of helium + 2 moles of oxygen + 1 mole s of carbon = 6 moles.

of the total of moles, 2 are oxygen, so the fraction of oxygen in the container is [tex]2/6 = 1/3[/tex]

Thus, the partial pressure of the oxygen gas must be a third of the total pressure in the container:

Partial pressure of the oxygen gas = [tex]\frac{786kPa}{3} = 262 kPa\\[/tex]

The answer is B. 262 kPa

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