Respuesta :

tl12502
the solution to the equation is r= the square root  of 56(b+2)
[tex]5r^{2} [/tex] - 12 = 68
[tex]5r^{2} [/tex] = 68 + 12
[tex]5r^{2} [/tex] = 80
[tex]r^{2} [/tex] = 80 ÷ 2
[tex]r^{2} [/tex] = 16
r = [tex] \sqrt{16} [/tex]
r = 4 or -4

So r = 4 or -4

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