mathisfun14
contestada

Prove that:

a) 5^31–5^29 is divisible by 100.
The answer should be in this format: ____ * 100

b) 25^9+5^17 is divisible by 30.
The answer should be in this format: ____ * 30

c) 27^10–9^14 is divisible by 24.
The answer should be in this format: ____ * 24

Respuesta :

Kalahira
(a) 5^31-5^29 = 5^29(5^2-1)

 = 5^29(24)
 = 5^29(6)(4)
 =5^26(6)*[(5)(5)(4)]
 =5^26(6)*100
  (b) 25^9+5^17 = 5^18+5^17 
=5^17(5+1)
 =5^17(6)
 =5^16[(5)(6)]
 =5^16*30 
 (c) 27^10–9^14 = 3^30-3^28
 =3^28(3^2 -1)
 =3^28(8)
 =3^27[(3)(8)]
 =3^27*24

BunnyBun2222

Answer:

6*5^27*100

Step-by-step explanation:

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